Write a program in Java to find out the second smallest digit of a given number without using arrays

Question: Write a program in Java to find out the second smallest digit of a given number without using arrays.

Welcome to Programming Questions !!!. In this post, I will share the code to find out the second smallest digit of a given number without using the array. This question is frequently asked in google question hub, so in this post, you will get its solution.

Sample Input 1:

Enter Number Here --> 5281036974

Sample Output 1:

The Second Smallest number is 1

Sample Input 2:

Enter Number Here --> 333

Sample Output 2:

All digits of the given number are same, hence there is no second smallest number

Solution code:

import java.util.Scanner;
public class secondSmallest {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("Enter Number Here --> ");
        String number = in.nextLine();
        in.close();
        int smallest = -1;
        int secondSmallest = -1;
        boolean flag = true;
        for (int i = 0; i < 10; i++) {
            for (int j = 0; j < number.length(); j++) {
                if (number.charAt(j) - 48 == i && smallest != -1 && smallest != i) {
                    secondSmallest = i;
                    flag = false;
                }
                if (number.charAt(j) - 48 == i)
                    smallest = i;
            }
            if (flag == false)
                break;
        }
        if (secondSmallest == -1)
            System.out.println("All digits of the given number are same, hence there is no second smallest number");
        else
            System.out.println("The Second Smallest number is " + secondSmallest);
    }
}

I hope that this answer will help you. If you have any question then do not keep it in your mind, put in front of all so that everyone could get its answer.

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